What is the required water horsepower for a centrifugal pump pumping 200 gallons per minute against 40 feet total dynamic head?

To determine the required water horsepower for the centrifugal pump, we can use the formula for hydraulic horsepower (HP), which is given by:

[ \text{Hydraulic HP} = \frac{(\text{Flow Rate in GPM} \times \text{Total Dynamic Head in Feet})}{3960} ]

First, we substitute in the values from the question:

• Flow Rate = 200 gallons per minute (GPM)

• Total Dynamic Head = 40 feet

Putting these values into the formula:

[ \text{Hydraulic HP} = \frac{(200 , \text{GPM} \times 40 , \text{feet})}{3960} ]

Calculating this gives:

[ \text{Hydraulic HP} = \frac{8000}{3960} \approx 2.02 , \text{HP} ]

When rounded, this results in a requirement of approximately 2.0 HP. Thus, the closest and correct choice for the required water horsepower when considering standard values and rounding conventions is 2.0 HP.

This indicates that the pump must be capable of delivering at least this amount of power to effectively lift the specified volume against the given head