What is the total suspended solids concentration given a sample volume of 750 mL, final mass of 50.1864 g, and initial mass of 50.1743 g?

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Multiple Choice

What is the total suspended solids concentration given a sample volume of 750 mL, final mass of 50.1864 g, and initial mass of 50.1743 g?

Explanation:
To determine the total suspended solids (TSS) concentration in the sample, we first need to find the mass of the suspended solids. This is done by subtracting the initial mass of the sample from the final mass after the solids have been filtered from the water. 1. Calculate the mass of suspended solids: Final mass = 50.1864 g Initial mass = 50.1743 g Mass of suspended solids = Final mass - Initial mass = 50.1864 g - 50.1743 g = 0.0121 g. 2. Convert the mass of suspended solids into milligrams: 0.0121 g = 12.1 mg. 3. To find the concentration in milligrams per liter (mg/L), we need to relate this mass to the volume of the sample in liters. Since the sample volume is 750 mL, convert this to liters: 750 mL = 0.750 L. 4. Now calculate the concentration: Concentration (mg/L) = (Mass of suspended solids in mg) / (Volume of sample in L) Concentration = 12.1 mg / 0.750 L ≈ 16

To determine the total suspended solids (TSS) concentration in the sample, we first need to find the mass of the suspended solids. This is done by subtracting the initial mass of the sample from the final mass after the solids have been filtered from the water.

  1. Calculate the mass of suspended solids:

Final mass = 50.1864 g

Initial mass = 50.1743 g

Mass of suspended solids = Final mass - Initial mass = 50.1864 g - 50.1743 g = 0.0121 g.

  1. Convert the mass of suspended solids into milligrams:

0.0121 g = 12.1 mg.

  1. To find the concentration in milligrams per liter (mg/L), we need to relate this mass to the volume of the sample in liters. Since the sample volume is 750 mL, convert this to liters:

750 mL = 0.750 L.

  1. Now calculate the concentration:

Concentration (mg/L) = (Mass of suspended solids in mg) / (Volume of sample in L)

Concentration = 12.1 mg / 0.750 L ≈ 16

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